Calculating how many bander/boots runs are available

[lostcalpolydude]

That will work as long as it hasn't run out. That effect isn't used up by free runaways, so it's probably good enough for this purpose.

 

[Deathless Assassin]

Alrighty, my plan of attack is add a function that simply adds two or zero as appropriate to remainingRuns().

int fam_weight()
	{
    return familiar_weight( my_familiar() ) + numeric_modifier("familiar weight") ;
	}

int remainingRuns()
	{
    return fam_weight() / 5 [B]+ bootsFeasted()[/B] - get_property( "_banderRunaways" ).to_int();
	}

Look good? My problem is figuring out how to evaluate whether _feastedFamiliars contains stomping boots. Here's my shot in the dark below:

int bootsFeasted()
	string_check()
	{
	if(contains_text("_feastedFamiliars" , "Stomping Boots"))
		{
		2
		}
	0
	}

As a failsafe against the boots and feast having been used previously in the day, I'm including this:

if (fam_weight() =/= familiar_weight( my_familiar() ))
Abort("Check whether you've used a moveable feast")

Would that successfully abort if the functions weight didn't match the familiars actual listed weight?